A body of weight $200 \mathrm{~N}$ is suspended from a tree branch through a chain of mass $10 \mathrm{~kg}$…

A body of weight $200 \mathrm{~N}$ is suspended from a tree branch through a chain of mass $10 \mathrm{~kg}$. The branch pulls the chain by a force equal to (if $g=10 \mathrm{~m} / \mathrm{s}^2$ ) :
  1. $100 \mathrm{~N}$
  2. $200 \mathrm{~N}$
  3. $300 \mathrm{~N}$
  4. $150 \mathrm{~N}$

Solution


Chain block system is in equilibrium so $\mathrm{T}=200+100=300 \mathrm{~N} \text {. }$

Asked in: JEE Main 2024 (06 Apr Shift 2)

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