A body of radius R and mass m is rolling horizontally without slipping with speed v . It then rolls up a hill to a maximum height h = 3 v 2 4 g . The body might be a

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Aicharya · Accepted Answer

Let I bt the moment of inertia of the body. Then total K E = 1 2 m v 2 + 1 2 I ω 2 or K E = 1 2 m v 2 + 1 2 I v 2 R 2 ω = v R According to energy conservation loss in K E = g a i n in P E . or 1 2 m + I R 2 v 2 = m g h = m g 3 v 2 4 g Solving this, we get I = 1 2 m R 2 i.e., the solid body is a disc

A body of radius R and mass m is rolling horizontally without slipping with speed v . It then rolls up a…

Solution