A body of mass m 1 moving with an unknown velocity of v 1 i ^ , undergoes a collinear collision with a body…

A body of mass m1 moving with an unknown velocity of v1 i^,  undergoes a collinear collision with a body of mass m2 moving with a velocity v2 i^. After the collision, m1 and m2 move with velocities of v3 i^ and v4 i^, respectively. If m2=0.5 m1 and v3=0.5 v1, then v1 is:
  1. v4-v24
  2. v4-v22
  3. v4+v2
  4. v4-v2

Solution

From the conservation of linear momentum,
m1v1+m2v2=m1v3+m2v4
m1v1+0.5 m1 v2=m10.5 v1+0.5 m1 v4
0.5 v1+0.5 v2=0.5 v4
v4=v1+v2
v1=v4-v2

Asked in: JEE Main 2019 (08 Apr Shift 2)

Practice more Center of Mass Momentum and Collision questions on Aicharya