A body of mass 'M' moving with velocity 'V' explodes into two equal parts. If one part comes to rest and the…

A body of mass 'M' moving with velocity 'V' explodes into two equal parts. If one part comes to rest and the other part moves with velocity ' $\mathrm{v}_{0}$ ', what would be the value of $^{\prime} \mathrm{V}_{0}$ '?
  1. V
  2. $\frac{\mathrm{V}}{\sqrt{2}}$
  3. $2 \mathrm{~V}$
  4. $4 \mathrm{~V}$

Solution

Given, the body of mass $M$ moving with velocity $V$ exploded into two equal parts - $M$ will explode in M/2 and M/2 masses - One with zero velocity and other with v
By the law of conservation of momentum Initial Momentum = Final Momentum $\begin{aligned} & M V=\frac{M}{2} \times 0+\frac{M}{2} \times v \\ & \Rightarrow v=2 V \end{aligned}$ :

Asked in: MHT CET 2020 (13 Oct Shift 1)

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