A body of mass M moving at speed V 0 collides elastically with a mass m at rest. After the collision, the…

A body of mass M moving at speed V0 collides elastically with a mass m at rest. After the collision, the two masses move at angles θ1 and θ2 with respect to the initial direction of motion of the body of mass M.. The largest possible value of the ratio Mm, for which the angles θ1 and θ2 will be equal, is :
  1. 3
  2. 4
  3. 2
  4. 1

Solution


Linear momentum conservation
(i) y-direction
mv2sinθ=mv1sinθ
mv2=mv1           ...(1)
(ii) x-direction
mv0=mv2cosθ+mv1cosθ            ...(2)
from (1) and (2)
mv0=mv2cosθ+mv2cosθ
mv0=2mv2cosθ       ...(3)
(iii) e=1given
v2-v1cos2θv0cosθ=1
v2-v1cos2θ=v0cosθ       ...(4)
v2-m22Mcos2θ=v0cosθ
v21-mMcos2θ=v0cosθ
mv02mcosθ1-mMcos2θ=v0cosθ
M-mcos2θ=2mcos2θ
M=2mcos2θ+m2cos2θ-1
Mm=4cos2θ-1
Mmmax=4-1=3

Asked in: JEE Main 2021 (31 Aug Shift 1)

Practice more Center of Mass Momentum and Collision questions on Aicharya