A body of mass M at rest explodes into three pieces, in the ratio of masses 1 : 1 : 2 . Two smaller pieces…

A body of mass M at rest explodes into three pieces, in the ratio of masses 1:1:2. Two smaller pieces fly off perpendicular to each other with velocities of 30 m s-1 and 40 m s-1 respectively. The velocity of the third piece will be
  1. 35 m s-1
  2. 50 m s-1
  3. 25 m s-1
  4. 15 m s-1

Solution

Let the masses of the three parts be m', m' and 2m'.

Momentum of first part p1=m'×30=30m' and momentum of second part p2=m'×40=40m'.

Third part will fly in a direction opposite to the direction of resultant of p1 and p2, so that total momentum of the system after explosion remains zero.

Momentum of the third part is p3=p12+p22=30m'2+40m'2=50m'

Velocity of third part, v=50m'2m'=25 m s-1

Asked in: JEE Main 2022 (29 Jun Shift 1)

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