A body of mass $m$ is suspended to an ideal spring of force constant $k$. The expected change in the…
A body of mass $m$ is suspended to an ideal spring of force constant $k$. The expected change in the position of the body due to an additional force $F$ acting vertically downwards is
$\frac{3 F}{2 k}$
$\frac{2 F}{k}$
$\frac{5 F}{2 k}$
$\frac{4 F}{k}$
Solution
Let the change in position of the body due to additional force is $x$.
So,
$\begin{aligned}
& F=\frac{1}{2} k x \\
& x=\frac{2 F}{k}
\end{aligned}$
$\therefore \quad x=\frac{2 F}{k}$