A body of mass 4 kg experiences two forces F → 1 = 5 i ^ + 8 j ^ + 7 k ^ and F → 2 = 3 i ^ - 4 j ^ - 3 k . ^…

A body of mass 4 kg experiences two forces F→1=5i^+8j^+7k^ and F→2=3i^-4j^-3k.^ The acceleration acting on the body is:
  1. -2i^-j^-k^
  2. 4i^+2j^+2k^
  3. 2i^+j^+k^
  4. 2i^+3j^+3k^

Solution

Net force F→=F→1+F→2=8i^+4j^+4k^

Therefore, required acceleration a→=F→m=2i^+j^+k^

Asked in: JEE Main 2024 (01 Feb Shift 2)

Practice more Laws of Motion questions on Aicharya