A body of mass 2   kg moving with a speed of 4   m   s - 1 makes an elastic collision with another body at rest and continues to move in the original direction but with one fourth of its initial speed. The speed of the two body centre of mass is $x/10$. Find the value of x.

Question

A body of mass 2 &#160; kg moving with a speed of 4 &#160; m &#160; s - 1 makes an elastic collision with another body at rest and continues to move in the original direction but with one fourth of its initial speed. The speed of the two body centre of mass is $x/10$. Find the value of x.

Aicharya · Accepted Answer

p i = p f 2 &#215; 4 = 2 &#215; 1 + m 2 &#215; v 2 m 2 v 2 = 6 &#160; &#8230; ( 1 ) By coefficient of restitution, 1 = v 2 - 1 4 &#8658; v 2 = 5 &#160; m &#160; s - 1 by ( i ) m 2 &#215; 5 = 6 m 2 = 1 . 2 &#160; kg v cm = m 1 v 1 + m 2 v 2 &#160; m 1 + m 2 v cm = 2 &#215; 1 + 1 . 2 &#215; 5 2 + 1 . 2 = 8 3 . 2 = 25 10 x = 25

A body of mass 2   kg moving with a speed of 4   m   s - 1 makes an elastic collision with…

Solution

A body of mass 2 &#160; kg moving with a speed of 4 &#160; m &#160; s - 1 makes an elastic collision with…

Solution

A body of mass 2 kg moving with a speed of 4 m s - 1 makes an elastic collision with…