A body of mass 2   kg moves under a force of 2 i ^ + 3 j ^ + 5 k ^ N It starts from rest and was at the…

A body of mass 2 kg moves under a force of 2i^+3j^+5k^N It starts from rest and was at the origin initially. After 4 s, its new coordinates are 8,b,20. The value of b is ______.

(Round off to the Nearest Integer)

Solution

a=Fm=2i^+3j^+5k^2

=i^+1.5j^+2.5k^

τ=ut+12at2

=0+12i^+1.5j^+2.5k^16

=8i^+12j^+20k^

b=12

Asked in: JEE Main 2021 (16 Mar Shift 2)

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