A body of mass 2 kg collides head on with another body of mass 4 kg . If the relative velocities of the bodies before and after collision are $10 \mathrm{~ms}^{-1}$ and $4 . \mathrm{ms}^{-1}$ respectively, the loss of kinetic energy of the system due to the collision is

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Aicharya · Accepted Answer

$\mathrm{m}_1=2 \mathrm{~kg}, \mathrm{~m}_2=4 \mathrm{~kg}, \mathrm{u}_1-\mathrm{u}_2=10 \mathrm{~ms}^{-1}, \mathrm{v}_2-\mathrm{v}_1=4 \mathrm{~ms}^{-1}$ $e=\frac{v_2-v_1}{u_1-u_2}=\frac{4}{10}=\frac{2}{5}$ $	herefore$ Loss of kinetic energy, $\Delta \mathrm{k}=\frac{1}{2}\left(\frac{\mathrm{~m}_1 \mathrm{~m}_2}{\mathrm{~m}_1+\mathrm{m}_2}ight)\left(\mathrm{u}_1-\mathrm{u}_2ight)^2\left(1-\mathrm{e}^2ight)$ $=\frac{1}{2}\left(\frac{2 	imes 4}{2+4}ight)(10)^2\left(1-\frac{4}{25}ight)=56 \mathrm{~J}$

A body of mass 2 kg collides head on with another body of mass 4 kg . If the relative velocities of the…

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