A body of mass 2 kg begins to move under the action of a time dependent force given by F → = 6 t i ^ + 6 t 2…

A body of mass 2 kg begins to move under the action of a time dependent force given by F=6t i^+6t2 j^ N. The power developed by the force at the time t is given by:
  1. 6t4+9t5 W
  2. 3t3+6t5 W
  3. 9t5+6t3 W
  4. 9t3+6t5 W

Solution

Given: F=6t i^+6t2 j^ N

Now, F=ma=6t i^+6t2 j^

a=Fm=3t i^+3t2 j^

Hence, velocity v=0tadt=3t22i^+t3j^

Required power, P=F.v=9t3+6t5 W

Asked in: JEE Main 2024 (31 Jan Shift 2)

Practice more Work Power Energy questions on Aicharya