A body of mass 1.5 kg is moving towards south with a uniform velocity of $8 \mathrm{~ms}^{-1}$. A force of 6 N is applied to the body towards east. The displacement of the body 3 seconds after the application of the force is

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Aicharya · Accepted Answer

$\begin{aligned} & \mathrm{m}=1.5 \mathrm{~kg}, \mathrm{~F}=6 \mathrm{~N} \\ & \overrightarrow{\mathrm{v}}=-8 \hat{\mathrm{j}}, \mathrm{t}=3 \mathrm{~s} \\ & \overrightarrow{\mathrm{a}}=\left(\frac{\mathrm{f}}{\mathrm{~m}}\right) \hat{\mathrm{i}}=\left(\frac{6}{1.5}\right) \hat{\mathrm{i}}=4 \hat{\mathrm{i}} \end{aligned}$ $\begin{aligned} & \therefore \quad \text { Displacement, } \overrightarrow{\mathrm{s}}=\overrightarrow{\mathrm{v}} \mathrm{t}+\frac{1}{2} \overrightarrow{\mathrm{a}} \mathrm{t}^2 \\ & \therefore \quad \overrightarrow{\mathrm{~s}}=-(8 \hat{\mathrm{j}}) \times 3+\frac{1}{2}(4 \hat{\mathrm{i}}) \times 9=-24 \hat{\mathrm{j}}+18 \hat{\mathrm{i}} \\ & \therefore \quad \mathrm{~S}=\sqrt{(18)^2+(-24)^2}=30 \mathrm{~m} \end{aligned}$

A body of mass 1.5 kg is moving towards south with a uniform velocity of $8 \mathrm{~ms}^{-1}$. A force of 6…

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