A body of mass \(10 \mathrm{~kg}\) has constant velocity of \(10 \mathrm{~m} \mathrm{~s}^{-1}\). A constant…

A body of mass \(10 \mathrm{~kg}\) has constant velocity of \(10 \mathrm{~m} \mathrm{~s}^{-1}\). A constant force is applied for a duration of \(4 \mathrm{~s}\) on the object and gives it a speed of \(2 \mathrm{~m} \mathrm{~s}^{-1}\) in opposite direction. Then, find acceleration produced in it.
  1. \(3 \mathrm{~ms}^{-2}\)
  2. \(-3 \mathrm{~ms}^{-2}\)
  3. \(0.3 \mathrm{~ms}^{-2}\)
  4. \(-0.3 \mathrm{~ms}^{-2}\)

Solution

Mass of body, \(m=10 \mathrm{~kg}\) Velocity, \(v=10 \mathrm{~ms}^{-1}\) \(t=4 \mathrm{~s}\) Final velocity of the body, \(v=-2 \mathrm{~ms}^{-1}\) Since, final velocity of the body decreases on application of constant force, hence acceleration is negative. By first equation of motion, $\begin{aligned} & v = u + a t \\ & \quad a = \frac{v-u}{t} = \frac{-2-10}{4} = -\frac{12}{4} = -3 \, \mathrm{ms}^{-2} \end{aligned}$

Asked in: AP EAMCET 2020 (17 Sep Shift 2)

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