A body of mass 0 . 5   kg travels on straight line path with velocity v = 3 x 2 + 4   m   s -…

A body of mass 0.5 kg travels on straight line path with velocity v=3x2+4 m s-1. The net work done by the force during its displacement from x=0 to x=2 m is
  1. 64 J
  2. 60 J
  3. 120 J
  4. 128 J

Solution

Given: v=3x2+4

Initial and final velocities are vi=302+4=4 m s-1

and vf=322+4=16 m s-1

From work-energy theorem,

⇒ΔKE=12mvf2-vi2

⇒ΔKE=12×12162-42

⇒ΔKE=W=60 J

Asked in: JEE Main 2022 (25 Jul Shift 1)

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