A body is suspended by a light string. The tensions in the string when the body is in air, when the body is…

A body is suspended by a light string. The tensions in the string when the body is in air, when the body is totally immersed in water and when the body is totally immersed in a liquid are respectively $40.2 \mathrm{~N}$, $28.4 \mathrm{~N}$ and $16.6 \mathrm{~N}$. The density of the liquid is
  1. $1200 \mathrm{~kg} \mathrm{- \textrm {m } ^ { - 3 }}$
  2. $1600 \mathrm{~kg}-\mathrm{m}^{-3}$
  3. $2000 \mathrm{~kg}-\mathrm{m}^{-3}$
  4. $2400 \mathrm{~kg}-\mathrm{m}^{-3}$

Solution

Density of water-Density of air $\propto T_{\text {water }}-T_{\text {air }}$ Density of liquid-Density of water $\propto T_{\text {liquid }}-T_{\text {water }}$ Now, from given values, $T_{\text {water }}-T_{\text {air }}=T_{\text {liquid }}-T_{\text {water }}$ Air density $=1 \mathrm{~kg} / \mathrm{m}^3$ and water density $=1000 \mathrm{~kg} / \mathrm{m}^3$ So, liquid density $\approx 2000 \mathrm{~kg} / \mathrm{m}^3$

Asked in: AP EAMCET 2018 (22 Apr Shift 1)

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