A body is projected at an angle of $45^{\circ}$ with the horizontal with a velocity of $60 \sqrt{2}…

A body is projected at an angle of $45^{\circ}$ with the horizontal with a velocity of $60 \sqrt{2} \mathrm{~ms}^{-1}$. Then the angle made by its velocity with the horizontal after $6 \mathrm{~s}$ is
  1. $45^{\circ}$
  2. $0^{\circ}$
  3. $30^{\circ}$
  4. $60^{\circ}$

Solution

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Asked in: AP EAMCET 2017 (24 Apr Shift 1)

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