A body is performing S.H.M. of amplitude 'A'. The displacement of the body from a point where kinetic energy…
A body is performing S.H.M. of amplitude 'A'. The displacement of the body from a point where kinetic energy is maximum to a point where potential energy is maximum, is
zero
$\pm \mathrm{A}$
$\pm \frac{\mathrm{A}}{2}$
$\pm \frac{\mathrm{A}}{4}$
Solution
Kinetic energy is maximum at the mean position and potential energy is maximum at the extreme positions on either side, The distance between mean and extreme position is A.