A body is moving along the horizontal surface with a velocity of $4 \mathrm{~m} / \mathrm{s}$. If the…
A body is moving along the horizontal surface with a velocity of $4 \mathrm{~m} / \mathrm{s}$. If the coefficient of kinetic friction is $0.2$, the distance travelled by body before coming to rest is $\left(\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^{2}\right)$
$8 \mathrm{~m}$
$16 \mathrm{~m}$
$4 \mathrm{~m}$
$6 \mathrm{~m}$
Solution
$f=\mu \mathrm{mg}$.
$\therefore a=-f / m=-\frac{\mu m g}{m}=-\mu g=-(0.2) 10=-2$
$v^{2}=u^{2}+2 a s$
$s=4$
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