A boat is moving due east in a region where the earth's magnetic field is $3.6 \times 10^{-5} \mathrm{~N} /…

A boat is moving due east in a region where the earth's magnetic field is $3.6 \times 10^{-5} \mathrm{~N} / \mathrm{Am}$ due north and horizontal. The boat carries a vertical conducting rod 2 m long. If the speed of the boat is $2.00 \mathrm{~m} / \mathrm{s}$, the magnitude of the induced e.m.f. in the rod is
  1. 1.4 mV
  2. $\quad 0.54 \mathrm{mV}$
  3. 0.72 mV
  4. 0.144 mV

Solution

$\begin{aligned} \mathrm{e} & =\mathrm{B} \times \mathrm{v} \times l \\ & =3.6 \times 10^{-5} \times 2 \times 2 \\ & =14.4 \times 10^{-5} \\ & =0.144 \mathrm{mV}\end{aligned}$ ~

Asked in: MHT CET 2024 (11 May Shift 1)

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