A block of mass $10 \mathrm{~kg}$ placed on the rough horizontal surface having coefficient of friction…

A block of mass $10 \mathrm{~kg}$ placed on the rough horizontal surface having coefficient of friction $\mu=0.5$, if a horizontal force of $100 \mathrm{~N}$ acting on it then acceleration of the block will be: \(\left(\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^{2}\right)\)
  1. $10 \mathrm{~ms}^{-1}$
  2. $5 \mathrm{~ms}^{-2}$
  3. $15 \mathrm{~ms}^{-2}$
  4. $0.5 \mathrm{~ms}^{-2}$

Solution

Here $f_{\max }=\mu N=\mu m g$ $=0.5 \times 10 \times 10=50 \mathrm{~N}$ $\Rightarrow a=\frac{\text { net force }}{\text { mass }}$ $=\frac{100-50}{10}=5 \mathrm{~m} / \mathrm{sec}^2$

Asked in: NEET 2002

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