A block of mass m slides on the wooden wedge, which in turn slides backward on the horizontal surface. The…

A block of mass m slides on the wooden wedge, which in turn slides backward on the horizontal surface. The acceleration of the block with respect to the wedge is:
Given m=8 kg, M=16 kg
Assume all the surfaces shown in the figure to be frictionless.

  1. 35 g
  2. 43 g
  3. 65 g
  4. 23g

Solution

Ncos60°=Ma1=16a1
N=32a1
to incline

N=8gcos30°-8a1sin30°32a1=443g-4a1

  a2=39g

Along incline

8gsin30°+8a1cos30°=ma2=8a2

a2=g×12+39g·32=2g3

Asked in: JEE Main 2021 (01 Sep Shift 2)

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