A block of mass m slides along a floor while a force of magnitude F is applied to it at an angle θ as…

A block of mass m slides along a floor while a force of magnitude F is applied to it at an angle θ as shown in figure. The coefficient of kinetic friction is μK. Then, the block's acceleration a is given by : (g is acceleration due to gravity)

  1. -Fmcosθ-μKg-Fmsinθ
  2. Fmcosθ-μKg-Fmsinθ
  3. Fmcosθ-μKg+Fmsinθ
  4. Fmcosθ+μKg-Fmsinθ

Solution

N=mg-fsinθ

Fcosθ-μkN=ma

Fcosθ-μkmg-Fsinθ=ma

a=Fmcosθ-μKg-Fmsinθ

Asked in: JEE Main 2021 (16 Mar Shift 1)

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