A block of mass m is placed on a surface with a vertical cross section given by y = x 3 6 . If the…

A block of mass m is placed on a surface with a vertical cross section given by y=x36. If the coefficient of friction is 0.5, the maximum height above the ground at which the block can be placed without slipping is 
  1. 16 m
  2. 23 m
  3. 13 m
  4. 12 m

Solution

For block remain stationary.

μ=tanθ (θ is angle at that point)

tanθ=μ=12(slope)

y=x36

dydx=3x26=x22slope=12x=1

y=(1)36 =16 m

Asked in: JEE Main 2014 (06 Apr)

Practice more Laws of Motion questions on Aicharya