A block of mass $2 \mathrm{~kg}$ is pulled at a constant speed with a taut rope along a frictionless plane that is inclined at $30^{\circ}$. Then the work done by the tension in the rope in pulling it a distance $4 \mathrm{~m}$ along the inclined plane in joule is $\left(\right.$ acceleration due…

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A block of mass $2 \mathrm{~kg}$ is pulled at a constant speed with a taut rope along a frictionless plane that is inclined at $30^{\circ}$. Then the work done by the tension in the rope in pulling it a distance $4 \mathrm{~m}$ along the inclined plane in joule is $\left(\right.$ acceleration due to gravity $=10 \mathrm{~ms}^{-2}$ )

Aicharya · Accepted Answer

As $V=$ constant $\begin{aligned} & \Rightarrow \mathrm{T}=\mathrm{mg} \sin \theta \\ & \Rightarrow \mathrm{T}=2 \times 10 \times \sin 30^{\circ} \\ & \Rightarrow \mathrm{T}=10 \mathrm{~N}\end{aligned}$ So, work done $=\mathrm{T} \times \mathrm{x}$ $=10 \times 4=40 \mathrm{~N}$

A block of mass $2 \mathrm{~kg}$ is pulled at a constant speed with a taut rope along a frictionless plane…

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