A block of mass $2 \mathrm{~kg}$ is placed on an inclined rough surface $\mathrm{AC}$ (as shown in figure) of coefficient of friction $\mu$. If $g=10 \mathrm{~ms}^{-2}$, the net force (in $\mathrm{N}$ ) on the block will be

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Aicharya · Accepted Answer

$\begin{aligned} \Rightarrow\left(F_{	ext {net }}ight) \mathrm{H} & =m g \sin 30^{\circ}-\mu m g \cos 30^{\circ} \ & =\frac{m g}{2}-\frac{1}{\sqrt{3}} m g \cdot \frac{\sqrt{3}}{2}\end{aligned}$ $F_{	ext {net }}=0$

A block of mass $2 \mathrm{~kg}$ is placed on an inclined rough surface $\mathrm{AC}$ (as shown in figure)…

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