A block of mass $4 \mathrm{~kg}$ is placed on a horizontal surface having coefficients of static and kinetic friction as $0 \cdot 5$ and $0 \cdot 4$ respectively. If a force, parallel to horizontal surface of $4 \mathrm{~N}$ is applied to the body, then the force of friction acting on the body…

Question

A block of mass $4 \mathrm{~kg}$ is placed on a horizontal surface having coefficients of static and kinetic friction as $0 \cdot 5$ and $0 \cdot 4$ respectively. If a force, parallel to horizontal surface of $4 \mathrm{~N}$ is applied to the body, then the force of friction acting on the body will be $\left[\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^{2}\right]$

Aicharya · Accepted Answer

For a block placed on a horizontal surface with coefficients of static and kinetic friction $\mu_s$ and $\mu_k$ respectively, if a force $F$ is applied parallel to the surface, the force of friction $F_{	ext {friction }}$ will depend on whether the block is moving or not: - If the applied force is less than the maximum static friction force $\left(F<F_{\max }ight.$ static $\left.=\mu_s m gight)$, the frictional force will be equal to the applied force and will prevent motion. - If the applied force exceeds the maximum static friction, the block will start to move, and the kinetic friction will take over, which is given by $F_{	ext {friction }}=\mu_k m g$. The correct answer would depend on the force applied and whether it exceeds the static friction limit, but more context is needed to determine the exact answer.

A block of mass $4 \mathrm{~kg}$ is placed on a horizontal surface having coefficients of static and kinetic…

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