A block $P$ of mass $M_P$ is in contact with another block $Q$ of mass $M_Q$ as shown in the fígure and they are placed on a smooth floor. Force on block Qis

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Aicharya · Accepted Answer

If $a$ be the common acceleration of system of blocks on application of force $F$. Free body diagram of block $P$ and $Q$ are given as

Hence, for block $P, F-R=M_P a$ For block $Q, R=M_Q a$ Adding Eqs. (i) and (ii), we get $ \Rightarrow \quad F=\frac{\left(M_P+M_Q\right) a}{M_P+M_Q} $ $\therefore$ Force on block $Q$ is given as $ R=M_Q a=M_Q \cdot \frac{F}{M_P+M_Q}=\frac{M_Q F}{M_P+M_Q} $

A block $P$ of mass $M_P$ is in contact with another block $Q$ of mass $M_Q$ as shown in the fígure and they…

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