A block of mass $2 \mathrm{~kg}$ is free to move along the $x$-axis. It is at rest and from $t$ $=0$ onwards…

A block of mass $2 \mathrm{~kg}$ is free to move along the $x$-axis. It is at rest and from $t$ $=0$ onwards it is subjected to a time-dependent force $F(t)$ in the $x$ direction. The force $F(t)$ varies with $t$ as shown in the figure. The kinetic energy of the block after $4.5 \mathrm{~s}$ is
  1. $4.50 \mathrm{~J}$
  2. $7.50 \mathrm{~J}$
  3. $5.06 \mathrm{~J}$
  4. $14.06 \mathrm{~J}$

Solution

Area under $F$ - $t$ graph $=$ momentum $ \begin{aligned} &=P=\sqrt{2 k m} \\ & \therefore \quad k=\frac{A^2}{2 m} \\ &(A=\text { net area of } F-t \text { graph) } \\ &=\frac{\left\{\left(\frac{4 \times 3}{2}\right)-\left(\frac{1.5 \times 2}{2}\right)\right\}^2}{2 \times 2}=5.0625 \mathrm{~J} \end{aligned} $ $\therefore$ The correct option is (c)

Asked in: JEE Advanced 2010 (Paper 2)

Practice more Work Power Energy questions on Aicharya