A block of mass 40   kg slides over a surface, when a mass of 4   kg is suspended through an…

A block of mass 40 kg slides over a surface, when a mass of 4 kg is suspended through an inextensible massless string passing over frictionless pulley as shown below.
The coefficient of kinetic friction between the surface and block is 0.02. The acceleration of block is: (Given g=10 m s-2.)

  1. 811 m s-2
  2. 1 m s-2
  3. 15 m s-2
  4. 45 m s-2

Solution

For hanging block, 

40-T=4a     ⋯1

Now, maximum value of friction force will be,

fmax=μN=0.02×40×10=8 N

For block on table, T-8=40a     ⋯2

From equation(1) and equation (2), we get32=44a ⇒a=3244=811 m s-2   

Asked in: JEE Main 2022 (29 Jun Shift 2)

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