A block of mass 100 kg slides over a distance of 10 m on a horizontal surface. If the co-efficient of…

A block of mass 100 kg slides over a distance of 10 m on a horizontal surface. If the co-efficient of friction between the surfaces is 0.4 , then the work done against friction (in J) is:
  1. 4200
  2. 3900
  3. 4000
  4. 4500

Solution

Given m=100 kg

s=10 m

μ=0.4

The frictional force is given by

 f=μmg=0.4×100×10=400 N

So, the work done by the force can be calculated as follows:

W=f×s=400×10=4000 J

Asked in: JEE Main 2024 (29 Jan Shift 1)

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