A block of mass 10   kg is moving along x -axis under the action of force F = 5 x   N . The work…

A block of mass 10 kg is moving along x-axis under the action of force F=5x N. The work done by the force in moving the block from x=2 m to 4 m will be _______ J.

Solution

Work done is W=∫Fdx

It is given that

F=5x N

So, work done is 

W=∫245xdx=5x2224⇒W=5(16-4)2=30 J

Asked in: JEE Main 2023 (15 Apr Shift 1)

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