A block of mass 10   k g is kept on a rough inclined plane as shown in the figure. A force of 3  …

A block of mass 10 kg is kept on a rough inclined plane as shown in the figure. A force of 3 N is applied on the block. The coefficient of static friction between the plane and the block is 0.6. What should be the minimum value of force P, such that the block does not move downward? (take g=10 ms-2 )

  1. 23 N
  2. 25 N
  3. 18 N
  4. 32 N

Solution



Block will be at rest

mgsin⁡θ+3N=P+f

10×10×12+3=P+μmgcos⁡θ

( ∵ To get P minimum friction must be minimum)

Pmin=502+3-0.6×10×10×12

=202+3=32N

Asked in: JEE Main 2019 (09 Jan Shift 1)

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