A block mass $m$ is placed on a smooth wedge of inclination $\theta$. The whole system is accelerated…
A block mass $m$ is placed on a smooth wedge of inclination $\theta$. The whole system is accelerated horizontally so that the block does not slip on the wedge. The force exerted by the wedge on the block ( $g$ is acceleration due to gravity) will be:
$m g \cos \theta$
$m g \sin \theta$
$m g$
$\mathrm{mg} / \cos \theta$
Solution
Here $N \cos \theta=m g$
$\Rightarrow N=\frac{m g}{\cos \theta}$
