A bird is tossing (flying to and fro) between two cars moving towards each other on a straight road. One car…
A bird is tossing (flying to and fro) between two cars moving towards each other on a straight road. One car has speed of $54 \mathrm{kmh}^{-1}$ while the other has the speed of $36 \mathrm{kmh}^{-1}$. The bird starts moving from first car towards
the other and is moving with the speed of $36 \mathrm{kmh}^{-1}$ where the two cars were separated by $36 \mathrm{~km}$. The total distance covered by the bird before the cars meet each other is
14400 m
1440 m
244 m
24400 m
Solution
The total time after the two cars which meet
$
=\frac{\text { Total distance }}{\text { Relative velocity of car w.r.t each other }}
$
$
T=\frac{36}{54+36} \Rightarrow T=\frac{36}{90}=0.4 h
$
In this duration, the distance travel by bird $=36 \times 0.4=14.4 \mathrm{~km}=14400 \mathrm{~m}$
Asked in: JEE Mains - Motion In One Dimension - Test 4