A bicycle tyre is filled with air having pressure of 270   kPa at 27 ° C . The approximate…

Given here, $P_1=270 \mathrm{kPa}, T_1=27+273=300 \mathrm{K}, T_2=36+273=309 \mathrm{K}$

Ideal gas equation is given by $PV=nRT$.

Considering isochoric process, i.e., constant volume so $P\propto T$

Thus, $\frac{P_1}{T_1}=\frac{P_2}{T_2}$

$\Rightarrow P_2=\frac{P_1}{T_1}\times T_2=\frac{270\times \left(309\right)}{300}$

$=278 \mathrm{kPa}$