A beam of white light is partially reflected and partially refracted from a surface. The angle between the…
- $70^{\circ}$
- $60^{\circ}$
- $55^{\circ}$
- $58^{\circ}$
Solution
Take angle of incidence $i$, angle of reflection $r$ and angle of refraction
$r_{\mathrm{F}}=30^{\circ}$
Given from geometry:
$\begin{aligned}
& r+r_{\mathrm{F}}+90^{\circ}=180^{\circ} \\
& \Rightarrow r=90^{\circ}-r_{\mathrm{F}}
\end{aligned}$
Since, angle of incidence is equal to the angle of reflection:
$\therefore i=r=90^{\circ}-r_F=90^{\circ}-30^{\circ}=60^{\circ}$Asked in: MHT CET 2022 (11 Aug Shift 1)