A beam of unpolarized light passes through a tourmaline crystal A and then it passes through a second…

A beam of unpolarized light passes through a tourmaline crystal A and then it passes through a second tourmaline crystal B oriented so that its principal plane is parallel to that of A. The intensity of emergent light is $\mathrm{I}_0$. Now $B$ is rotated by $45^{\circ}$ about the ray. The emergent light will have intensity $\left(\cos 45^{\circ}=\frac{1}{\sqrt{2}}\right)$
  1. $\frac{I_0}{2}$
  2. $\frac{I_0}{\sqrt{2}}$
  3. $\frac{\sqrt{2}}{I_0}$
  4. $\frac{2}{I_0}$

Solution

Using law of Malus, $\begin{aligned} \mathrm{I} & =\mathrm{I}_0 \cos ^2 \theta \\ & =\mathrm{I}_0\left(\cos ^2 45\right) \\ & =\mathrm{I}_0\left(\frac{1}{\sqrt{2}}\right)^2 \\ & =\frac{\mathrm{I}_0}{2} \end{aligned}$

Asked in: MHT CET 2023 (09 May Shift 1)

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