A bead of mass $100 \mathrm{~g}$ is attached to one end of a spring of natural length $L$ and spring…

A bead of mass $100 \mathrm{~g}$ is attached to one end of a spring of natural length $L$ and spring constant $k=\frac{(\sqrt{3}+1) m g}{L}$, where $m$ is the mass of bead. The other end of the spring is fixed at point $A$ on a smooth vertical ring of radius $R$ as shown in the figure. The normal reaction at $B$ just after it is released to move is (take, $g=9.8 \mathrm{~ms}^{-2}$ )
  1. $1.73 \mathrm{~N}$
  2. , $2.23 \mathrm{~N}$
  3. $2.44 \mathrm{~N}$
  4. $2.55 \mathrm{~N}$

Solution

Normal reaction $=$ Resultant of spring force $k x$ and weight $\mathrm{mg}$. $ =\sqrt{\left(k^2 x^2+m^2 g^2\right)}=2.55 \mathrm{~N} $

Asked in: AP EAMCET 2018 (23 Apr Shift 2)

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