A battery of emf $12 \mathrm{~V}$ and internal resistance $4 \Omega$ is connected to a resistor. The…

A battery of emf $12 \mathrm{~V}$ and internal resistance $4 \Omega$ is connected to a resistor. The resistance of the resistor if the current in the circuit is $0.8 \mathrm{~A}$ is
  1. $11 \Omega$
  2. $9 \Omega$
  3. $15 \Omega$
  4. $13 \Omega$

Solution

The circuit can be drawn as
Current in circuit, $I=\frac{E}{r+R}$ Substituting given values, we get, $0.8=\frac{12}{R+4}$ $\Rightarrow \quad R+4=15 \Rightarrow R=11 \Omega$

Asked in: AP EAMCET 2022 (08 Jul Shift 2)

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