A ball of mass $m$ moving with speed $v$ collides elastically with an identical stationary ball which is…

A ball of mass $m$ moving with speed $v$ collides elastically with an identical stationary ball which is initially at rest. After collision the first ball moves at an angle $\pi$ to its initial direction and has speed $\left(\frac{v}{3}\right)$. The second ball moves in a straight line after the collision. Then speed of the second ball after collision is
  1. $\frac{2}{\sqrt{3}} v$
  2. $\frac{2 \sqrt{2}}{3} v$
  3. $\frac{4}{3} v$
  4. $\frac{3}{\sqrt{2}} v$

Solution

For elastic collision: Using energy conservation, $\frac{1}{2} m_1 v_1^2+\frac{1}{2} m_2 v_2^2=\frac{1}{2} m_1 v_1^{\prime 2}+\frac{1}{2} m_2 v_2^{\prime 2}$ Here, $\frac{1}{2} m v^2+0=\frac{1}{2} m(v / 3)^2+\frac{1}{2} m v_2^{\prime 2}$ Or $v_2^{\prime 2}=\frac{8}{9} v^2$ Or $v_2^{\prime}=\frac{2 \sqrt{2}}{3} v$

Asked in: MHT CET 2022 (06 Aug Shift 1)

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