A ball of mass m moving with a velocity v strikes the bob of a pendulum at rest. The mass of the bob is also m . If the collision is perfectly inelastic, the height to which the bob will rise is given by h = v 2 x · g , then the value of x is

Question

Aicharya · Accepted Answer

Because the collision is perfectly inelastic, the two blocks stick together. By conservation of linear momentum,

2 m V = m v

or

V = \frac{v}{2}

By conservation of energy,

2 m g h = \frac{1}{2} \times 2 m V^{2}

or

h = \frac{v^{2}}{8 \cdot g}

A ball of mass m moving with a velocity v strikes the bob of a pendulum at rest. The mass of the bob is also…

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