A ball of mass 4   kg , moving with a velocity of 10   m   s - 1 , collides with a spring of…

A ball of mass 4 kg, moving with a velocity of 10 m s-1, collides with a spring of length 8 m and force constant 100 N m-1. The length of the compressed spring is x m. The value of x, to the nearest integer, is ___ .

Solution

Let's say the compression in the spring by:y. So, by work-energy theorem we have

12mv2=12ky2y=mk·vy=4100×10y=2 m

 Final length of spring,=8-2=6 m.

Asked in: JEE Main 2021 (18 Mar Shift 2)

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