A ball of mass 160   g is thrown up at an angle of 60 ° to the horizontal at a speed of 10  …

A ball of mass 160 g is thrown up at an angle of 60° to the horizontal at a speed of 10 m s-1. The angular momentum of the ball at the highest point of the trajectory with respect to the point from which the ball is thrown is nearly g=10 m s-2
  1. 1.73 kg m2 s-1
  2. 3.46 kg m2 s-1
  3. 3.0 kg m2 s-1
  4. 6.0 kg m2 s-1

Solution



The angular momentum L→=r→×p→

At maximum height angular momentum about O,

L=m vcosθ H

=mvcosθ×u2sin2θ2g        for horizontal v=u

=mu3sin260°cos60°2g

=3 kg m2 s-1

Asked in: JEE Main 2014 (19 Apr Online)

Practice more Rotational Motion questions on Aicharya