A ball of mass 0 . 5   kg moving horizontally at 10   m   s - 1 strikes a vertical wall and rebounds with speed v . The magnitude of the change in linear momentum is found to be 8 . 0   kg   m   s - 1 . The magnitude of v is,

Question

A ball of mass 0 . 5 &#160; kg moving horizontally at 10 &#160; m &#160; s - 1 strikes a vertical wall and rebounds with speed v . The magnitude of the change in linear momentum is found to be 8 . 0 &#160; kg &#160; m &#160; s - 1 . The magnitude of v is,

Aicharya · Accepted Answer

Linear momentum is a vector quantity.
Initial momentum $= + m \times 10 \hat{i}$ .
Final momentum $= - m v \hat{i}$
Change in linear momentum $= - 10 m \hat{i} - m v \hat{i} = - (10 + v) m \hat{i}$
Therefore,
$(10 + v) \times 0.5 = 8 \Rightarrow v = 16 - 10 = 6 m s^{- 1}$

A ball of mass 0 . 5   kg moving horizontally at 10   m   s - 1 strikes a vertical wall and…

Solution

A ball of mass 0 . 5 &#160; kg moving horizontally at 10 &#160; m &#160; s - 1 strikes a vertical wall and…

Solution

A ball of mass 0 . 5 kg moving horizontally at 10 m s - 1 strikes a vertical wall and…