A ball of mass 0 . 15 kg is dropped from a height 10 m strikes the ground and rebounds to the same height.…

$m=0.15 \mathrm{kg}; h=10 \mathrm{m}$

$v=\sqrt{2gh}=\sqrt{2\times 9.8\times 10}=14 \mathrm{m} {\mathrm{s}}^{-1}$

As we know,

Impulse$=$change in momentum

$$\begin{gathered} =p_f-p_i \\ =0.15\times 14-\left(-0.15\times 14\right) \end{gathered}$$

$=2\times 0.15\times 14$

$=4.2 \mathrm{kg} \mathrm{m} {\mathrm{s}}^{-1}$

( To raise back to same height, rebounds velocity is same as the hitting velocity)