A ball is thrown vertically. It has a speed of $10 \mathrm{~m} / \mathrm{sec}$ when it has reached one half…
A ball is thrown vertically. It has a speed of $10 \mathrm{~m} / \mathrm{sec}$ when it has reached one half of its maximum height. How high does the ball rise? Take $\mathrm{g}=10 \mathrm{~m} / \mathrm{s}^2$.
$10 \mathrm{~m}$
$5 \mathrm{~m}$
$15 \mathrm{~m}$
$20 \mathrm{~m}$
Solution
Using equation of motion
$V^2=u^2-2 g h$
After reading max height velocity because zero.
$\begin{aligned} 0 & =(10)^2-2 \times 10 \times \frac{1}{2} \\ \Rightarrow \quad h & =\frac{200}{20}=10 \mathrm{~m}\end{aligned}$