A ball is released from the top of a tower of height $h$ metres. It takes $T$ seconds to reach the ground.…
- $\mathrm{h} / 9$ metres from the ground
- $7 \mathrm{~h} / 9$ metres from the ground
- $8 \mathrm{~h} / 9$ metres from the ground
- $17 \mathrm{~h} / 18$ metres from the ground.
Solution
Asked in: JEE Main 2004