A ball is projected from the ground with a speed 15   m   s - 1 at an angle θ with horizontal…

A ball is projected from the ground with a speed 15 m s-1 at an angle θ with horizontal so that its range and maximum height are equal, then tanθ will be equal to
  1. 14
  2. 12
  3. 2
  4. 4

Solution

The range and the maximum height of the projectile are given as below,

R=u2sin2θg=2u2sinθcosθgH=u2sin2θ2g

Therefore,

As H=R

⇒tanθ=4

Asked in: JEE Main 2022 (25 Jul Shift 2)

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