A ball is dropped from the top of a 100   m high tower on a planet. In the last 1 2 s before hitting the ground, it covers a distance of 19   m . Acceleration due to gravity (in m   s - 2 ) near the surface on that planet is______

Question

A ball is dropped from the top of a 100 &#160; m high tower on a planet. In the last 1 2 s before hitting the ground, it covers a distance of 19 &#160; m . Acceleration due to gravity (in m &#160; s - 2 ) near the surface on that planet is______

Aicharya · Accepted Answer

g t - 1 2 2 2 &#215; 1 2 = 81 ... (1) 1 2 g t 2 = 100 &hellip;. (2) devide equation 1 &#160; &#38; &#160; 2 t t - 1 2 = 10 9 t = 5 &#160; s put t in equation 2 g = 8 &#160; m s 2

A ball is dropped from the top of a 100   m high tower on a planet. In the last 1 2 s before hitting…

Solution

A ball is dropped from the top of a 100 &#160; m high tower on a planet. In the last 1 2 s before hitting…

Solution

A ball is dropped from the top of a 100 m high tower on a planet. In the last 1 2 s before hitting…